Current File : //usr/lib/calibre/calibre/utils/text2int.py
#!/usr/bin/env python3
__author__ = "stackoverflow community"
__docformat__ = 'restructuredtext en'
"""
Takes english numeric words and converts them to integers.
Returns False if the word isn't a number.
implementation courtesy of the stackoverflow community:
http://stackoverflow.com/questions/493174/is-there-a-way-to-convert-number-words-to-integers-python
"""
import re
numwords = {}
def text2int(textnum):
if not numwords:
units = ["zero", "one", "two", "three", "four", "five", "six",
"seven", "eight", "nine", "ten", "eleven", "twelve",
"thirteen", "fourteen", "fifteen", "sixteen", "seventeen",
"eighteen", "nineteen"]
tens = ["", "", "twenty", "thirty", "forty", "fifty", "sixty",
"seventy", "eighty", "ninety"]
scales = ["hundred", "thousand", "million", "billion", "trillion",
'quadrillion', 'quintillion', 'sexillion', 'septillion',
'octillion', 'nonillion', 'decillion']
numwords["and"] = (1, 0)
for idx, word in enumerate(units):
numwords[word] = (1, idx)
for idx, word in enumerate(tens):
numwords[word] = (1, idx * 10)
for idx, word in enumerate(scales):
numwords[word] = (10 ** (idx * 3 or 2), 0)
ordinal_words = {'first':1, 'second':2, 'third':3, 'fifth':5,
'eighth':8, 'ninth':9, 'twelfth':12}
ordinal_endings = [('ieth', 'y'), ('th', '')]
current = result = 0
tokens = re.split(r"[\s-]+", textnum)
for word in tokens:
if word in ordinal_words:
scale, increment = (1, ordinal_words[word])
else:
for ending, replacement in ordinal_endings:
if word.endswith(ending):
word = f"{word[:-len(ending)]}{replacement}"
if word not in numwords:
# raise Exception("Illegal word: " + word)
return False
scale, increment = numwords[word]
if scale > 1:
current = max(1, current)
current = current * scale + increment
if scale > 100:
result += current
current = 0
return result + current
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